6-(2x+3)=7+8(2+x)

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Solution for 6-(2x+3)=7+8(2+x) equation:



6-(2x+3)=7+8(2+x)
We move all terms to the left:
6-(2x+3)-(7+8(2+x))=0
We add all the numbers together, and all the variables
-(2x+3)-(7+8(x+2))+6=0
We get rid of parentheses
-2x-(7+8(x+2))-3+6=0
We calculate terms in parentheses: -(7+8(x+2)), so:
7+8(x+2)
determiningTheFunctionDomain 8(x+2)+7
We multiply parentheses
8x+16+7
We add all the numbers together, and all the variables
8x+23
Back to the equation:
-(8x+23)
We add all the numbers together, and all the variables
-2x-(8x+23)+3=0
We get rid of parentheses
-2x-8x-23+3=0
We add all the numbers together, and all the variables
-10x-20=0
We move all terms containing x to the left, all other terms to the right
-10x=20
x=20/-10
x=-2

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