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6-(2x+6)x=1
We move all terms to the left:
6-(2x+6)x-(1)=0
We add all the numbers together, and all the variables
-(2x+6)x+5=0
We multiply parentheses
-2x^2-6x+5=0
a = -2; b = -6; c = +5;
Δ = b2-4ac
Δ = -62-4·(-2)·5
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{19}}{2*-2}=\frac{6-2\sqrt{19}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{19}}{2*-2}=\frac{6+2\sqrt{19}}{-4} $
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