6-(2z+4)=5-z

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Solution for 6-(2z+4)=5-z equation: 



6-(2z+4)=5-z

We move all terms to the left:

6-(2z+4)-(5-z)=0

We add all the numbers together, and all the variables

-(2z+4)-(-1z+5)+6=0

We get rid of parentheses

-2z+1z-4-5+6=0

We add all the numbers together, and all the variables

-1z-3=0

We move all terms containing z to the left, all other terms to the right

-z=3

z=3/-1

z=-3

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