6-(5/v+2)=(-4/(v-1))

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Solution for 6-(5/v+2)=(-4/(v-1)) equation: 


D( v )

v = 0

v-1 = 0

v = 0

v = 0

v-1 = 0

v-1 = 0

v-1 = 0 // + 1

v = 1

v in (-oo:0) U (0:1) U (1:+oo)

6-(5/v)-2 = -4/(v-1) // + -4/(v-1)

6-(-4/(v-1))-(5/v)-2 = 0

4*(v-1)^-1-5*v^-1-2+6 = 0

4/(v-1)-5/v-2+6 = 0

(4*v)/(v*(v-1))+(-5*(v-1))/(v*(v-1))+(-2*v*(v-1))/(v*(v-1))+(6*v*(v-1))/(v*(v-1)) = 0

6*v*(v-1)-5*(v-1)-2*v*(v-1)+4*v = 0

6*v^2-2*v^2-v+2*v-6*v+5 = 0

6*v^2-2*v^2+v-6*v+5 = 0

4*v^2-5*v+5 = 0

4*v^2-5*v+5 = 0

4*v^2-5*v+5 = 0

DELTA = (-5)^2-(4*4*5)

DELTA = -55

DELTA < 0

1 = 0

1/(v*(v-1)) = 0

1/(v*(v-1)) = 0 // * v*(v-1)

1 = 0

v belongs to the empty set

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