6-(5/w+2)=(2/w+1)

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Solution for 6-(5/w+2)=(2/w+1) equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

6-(5/w)-2 = 2/w+1 // - 2/w+1

6-(5/w)-(2/w)-2-1 = 0

6-5*w^-1-2*w^-1-2-1 = 0

-7*w^-1 = -3 // : -7

w^-1 = 3/7

-1 < 0

1/(w^1) = 3/7 // * w^1

1 = 3/7*w^1 // : 3/7

7/3 = w^1

w = 7/3

w = 7/3

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