6-(n+3)=3(n+5)-2n

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Solution for 6-(n+3)=3(n+5)-2n equation: 



6-(n+3)=3(n+5)-2n

We move all terms to the left:

6-(n+3)-(3(n+5)-2n)=0

We get rid of parentheses

-n-(3(n+5)-2n)-3+6=0



We calculate terms in parentheses: -(3(n+5)-2n), so:

3(n+5)-2n

We add all the numbers together, and all the variables

-2n+3(n+5)

We multiply parentheses

-2n+3n+15

We add all the numbers together, and all the variables

n+15

Back to the equation:

-(n+15)



We add all the numbers together, and all the variables

-1n-(n+15)+3=0

We get rid of parentheses

-1n-n-15+3=0

We add all the numbers together, and all the variables

-2n-12=0

We move all terms containing n to the left, all other terms to the right

-2n=12

n=12/-2

n=-6

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