6-(n-4)=3(n+2)

Solution for 6-(n-4)=3(n+2) equation:

Simplifying
6 + -1(n + -4) = 3(n + 2)

Reorder the terms:
6 + -1(-4 + n) = 3(n + 2)
6 + (-4 * -1 + n * -1) = 3(n + 2)
6 + (4 + -1n) = 3(n + 2)

Combine like terms: 6 + 4 = 10
10 + -1n = 3(n + 2)

Reorder the terms:
10 + -1n = 3(2 + n)
10 + -1n = (2 * 3 + n * 3)
10 + -1n = (6 + 3n)

Solving
10 + -1n = 6 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
10 + -1n + -3n = 6 + 3n + -3n

Combine like terms: -1n + -3n = -4n
10 + -4n = 6 + 3n + -3n

Combine like terms: 3n + -3n = 0
10 + -4n = 6 + 0
10 + -4n = 6

Add '-10' to each side of the equation.
10 + -10 + -4n = 6 + -10

Combine like terms: 10 + -10 = 0
0 + -4n = 6 + -10
-4n = 6 + -10

Combine like terms: 6 + -10 = -4
-4n = -4

Divide each side by '-4'.
n = 1

Simplifying
n = 1