6-(n-9)=3(n+4)

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Solution for 6-(n-9)=3(n+4) equation: 



6-(n-9)=3(n+4)

We move all terms to the left:

6-(n-9)-(3(n+4))=0

We get rid of parentheses

-n-(3(n+4))+9+6=0



We calculate terms in parentheses: -(3(n+4)), so:

3(n+4)

We multiply parentheses

3n+12

Back to the equation:

-(3n+12)



We add all the numbers together, and all the variables

-1n-(3n+12)+15=0

We get rid of parentheses

-1n-3n-12+15=0

We add all the numbers together, and all the variables

-4n+3=0

We move all terms containing n to the left, all other terms to the right

-4n=-3

n=-3/-4

n=3/4

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