6-(x+2)-3*(2x-4)=8*(4-x)+3*(x-4)

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Solution for 6-(x+2)-3*(2x-4)=8*(4-x)+3*(x-4) equation: 



6-(x+2)-3(2x-4)=8(4-x)+3(x-4)

We move all terms to the left:

6-(x+2)-3(2x-4)-(8(4-x)+3(x-4))=0

We add all the numbers together, and all the variables

-(x+2)-3(2x-4)-(8(-1x+4)+3(x-4))+6=0

We multiply parentheses

-(x+2)-6x-(8(-1x+4)+3(x-4))+12+6=0

We get rid of parentheses

-x-6x-(8(-1x+4)+3(x-4))-2+12+6=0



We calculate terms in parentheses: -(8(-1x+4)+3(x-4)), so:

8(-1x+4)+3(x-4)

We multiply parentheses

-8x+3x+32-12

We add all the numbers together, and all the variables

-5x+20

Back to the equation:

-(-5x+20)



We add all the numbers together, and all the variables

-7x-(-5x+20)+16=0

We get rid of parentheses

-7x+5x-20+16=0

We add all the numbers together, and all the variables

-2x-4=0

We move all terms containing x to the left, all other terms to the right

-2x=4

x=4/-2

x=-2

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