6-(x+2)=3x+4(x-3)

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Solution for 6-(x+2)=3x+4(x-3) equation: 



6-(x+2)=3x+4(x-3)

We move all terms to the left:

6-(x+2)-(3x+4(x-3))=0

We get rid of parentheses

-x-(3x+4(x-3))-2+6=0



We calculate terms in parentheses: -(3x+4(x-3)), so:

3x+4(x-3)

We multiply parentheses

3x+4x-12

We add all the numbers together, and all the variables

7x-12

Back to the equation:

-(7x-12)



We add all the numbers together, and all the variables

-1x-(7x-12)+4=0

We get rid of parentheses

-1x-7x+12+4=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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