6-(x-2)=3(3x+1)

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Solution for 6-(x-2)=3(3x+1) equation: 



6-(x-2)=3(3x+1)

We move all terms to the left:

6-(x-2)-(3(3x+1))=0

We get rid of parentheses

-x-(3(3x+1))+2+6=0



We calculate terms in parentheses: -(3(3x+1)), so:

3(3x+1)

We multiply parentheses

9x+3

Back to the equation:

-(9x+3)



We add all the numbers together, and all the variables

-1x-(9x+3)+8=0

We get rid of parentheses

-1x-9x-3+8=0

We add all the numbers together, and all the variables

-10x+5=0

We move all terms containing x to the left, all other terms to the right

-10x=-5

x=-5/-10

x=1/2

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