6-(y+3)=3(y-1)

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Solution for 6-(y+3)=3(y-1) equation: 



6-(y+3)=3(y-1)

We move all terms to the left:

6-(y+3)-(3(y-1))=0

We get rid of parentheses

-y-(3(y-1))-3+6=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We add all the numbers together, and all the variables

-1y-(3y-3)+3=0

We get rid of parentheses

-1y-3y+3+3=0

We add all the numbers together, and all the variables

-4y+6=0

We move all terms containing y to the left, all other terms to the right

-4y=-6

y=-6/-4

y=1+1/2

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