6-1/3w+7/5w=4

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Solution for 6-1/3w+7/5w=4 equation:



6-1/3w+7/5w=4
We move all terms to the left:
6-1/3w+7/5w-(4)=0
Domain of the equation: 3w!=0
w!=0/3
w!=0
w∈R
Domain of the equation: 5w!=0
w!=0/5
w!=0
w∈R
We add all the numbers together, and all the variables
-1/3w+7/5w+2=0
We calculate fractions
(-5w)/15w^2+21w/15w^2+2=0
We multiply all the terms by the denominator
(-5w)+21w+2*15w^2=0
We add all the numbers together, and all the variables
21w+(-5w)+2*15w^2=0
Wy multiply elements
30w^2+21w+(-5w)=0
We get rid of parentheses
30w^2+21w-5w=0
We add all the numbers together, and all the variables
30w^2+16w=0
a = 30; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·30·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*30}=\frac{-32}{60} =-8/15 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*30}=\frac{0}{60} =0 $

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