6-10j+6(5j+5)=4(j-9)

Solution for 6-10j+6(5j+5)=4(j-9) equation:

6-10j+6(5j+5)=4(j-9)

We move all terms to the left:

6-10j+6(5j+5)-(4(j-9))=0

We multiply parentheses

-10j+30j-(4(j-9))+30+6=0


We calculate terms in parentheses: -(4(j-9)), so:

4(j-9)

We multiply parentheses

4j-36

Back to the equation:

-(4j-36)


We add all the numbers together, and all the variables

20j-(4j-36)+36=0

We get rid of parentheses

20j-4j+36+36=0

We add all the numbers together, and all the variables

16j+72=0

We move all terms containing j to the left, all other terms to the right

16j=-72

j=-72/16

j=-4+1/2