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6-11/3x=1-x
We move all terms to the left:
6-11/3x-(1-x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-11/3x-(-1x+1)+6=0
We get rid of parentheses
-11/3x+1x-1+6=0
We multiply all the terms by the denominator
1x*3x-1*3x+6*3x-11=0
Wy multiply elements
3x^2-3x+18x-11=0
We add all the numbers together, and all the variables
3x^2+15x-11=0
a = 3; b = 15; c = -11;
Δ = b2-4ac
Δ = 152-4·3·(-11)
Δ = 357
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{357}}{2*3}=\frac{-15-\sqrt{357}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{357}}{2*3}=\frac{-15+\sqrt{357}}{6} $
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