6-2(2x+3)-4(3x+1)=1/3(9x-6)

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Solution for 6-2(2x+3)-4(3x+1)=1/3(9x-6) equation: 



6-2(2x+3)-4(3x+1)=1/3(9x-6)

We move all terms to the left:

6-2(2x+3)-4(3x+1)-(1/3(9x-6))=0



Domain of the equation: 3(9x-6))!=0

x∈R



We multiply parentheses

-4x-12x-(1/3(9x-6))-6-4+6=0

We multiply all the terms by the denominator


-4x*3(9x-6))-12x*3(9x-6))-(1-6*3(9x-6))-4*3(9x-6))+6*3(9x-6))=0

Wy multiply elements

-36x^3(9-6))-(1-6*3(9x-6))-4*3(9x-6))+6*3(9x-6))=0

We do not support expression: x^3(9

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