6-2(3-y=1)=-13y-2(6-y)

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Solution for 6-2(3-y=1)=-13y-2(6-y) equation: 



6-2(3-y=1)=-13y-2(6-y)

We move all terms to the left:

6-2(3-y-(1))=0

We add all the numbers together, and all the variables

-2(-1y+2)+6=0

We multiply parentheses

2y-4+6=0

We add all the numbers together, and all the variables

2y+2=0

We move all terms containing y to the left, all other terms to the right

2y=-2

y=-2/2

y=-1

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