6-2(3j-2)=4(1+j)

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Solution for 6-2(3j-2)=4(1+j) equation:


Simplifying
6 + -2(3j + -2) = 4(1 + j)

Reorder the terms:
6 + -2(-2 + 3j) = 4(1 + j)
6 + (-2 * -2 + 3j * -2) = 4(1 + j)
6 + (4 + -6j) = 4(1 + j)

Combine like terms: 6 + 4 = 10
10 + -6j = 4(1 + j)
10 + -6j = (1 * 4 + j * 4)
10 + -6j = (4 + 4j)

Solving
10 + -6j = 4 + 4j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-4j' to each side of the equation.
10 + -6j + -4j = 4 + 4j + -4j

Combine like terms: -6j + -4j = -10j
10 + -10j = 4 + 4j + -4j

Combine like terms: 4j + -4j = 0
10 + -10j = 4 + 0
10 + -10j = 4

Add '-10' to each side of the equation.
10 + -10 + -10j = 4 + -10

Combine like terms: 10 + -10 = 0
0 + -10j = 4 + -10
-10j = 4 + -10

Combine like terms: 4 + -10 = -6
-10j = -6

Divide each side by '-10'.
j = 0.6

Simplifying
j = 0.6

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