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6-2(6x+1)=2x-2(2x+8)
We move all terms to the left:
6-2(6x+1)-(2x-2(2x+8))=0
We multiply parentheses
-12x-(2x-2(2x+8))-2+6=0
We calculate terms in parentheses: -(2x-2(2x+8)), so:We add all the numbers together, and all the variables
2x-2(2x+8)
We multiply parentheses
2x-4x-16
We add all the numbers together, and all the variables
-2x-16
Back to the equation:
-(-2x-16)
-12x-(-2x-16)+4=0
We get rid of parentheses
-12x+2x+16+4=0
We add all the numbers together, and all the variables
-10x+20=0
We move all terms containing x to the left, all other terms to the right
-10x=-20
x=-20/-10
x=+2
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