6-2(x+3)=x+1

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Solution for 6-2(x+3)=x+1 equation: 



6-2(x+3)=x+1

We move all terms to the left:

6-2(x+3)-(x+1)=0

We multiply parentheses

-2x-(x+1)-6+6=0

We get rid of parentheses

-2x-x-1-6+6=0

We add all the numbers together, and all the variables

-3x-1=0

We move all terms containing x to the left, all other terms to the right

-3x=1

x=1/-3

x=-1/3

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