6-2(x+4)-12=-10+2(-x-2)

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Solution for 6-2(x+4)-12=-10+2(-x-2) equation: 



6-2(x+4)-12=-10+2(-x-2)

We move all terms to the left:

6-2(x+4)-12-(-10+2(-x-2))=0

We add all the numbers together, and all the variables

-2(x+4)-(-10+2(-1x-2))+6-12=0

We add all the numbers together, and all the variables

-2(x+4)-(-10+2(-1x-2))-6=0

We multiply parentheses

-2x-(-10+2(-1x-2))-8-6=0



We calculate terms in parentheses: -(-10+2(-1x-2)), so:

-10+2(-1x-2)

determiningTheFunctionDomain
2(-1x-2)-10

We multiply parentheses

-2x-4-10

We add all the numbers together, and all the variables

-2x-14

Back to the equation:

-(-2x-14)



We add all the numbers together, and all the variables

-2x-(-2x-14)-14=0

We get rid of parentheses

-2x+2x+14-14=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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