6-2(x+4)-4x=7+3(x+5)-6

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Solution for 6-2(x+4)-4x=7+3(x+5)-6 equation: 



6-2(x+4)-4x=7+3(x+5)-6

We move all terms to the left:

6-2(x+4)-4x-(7+3(x+5)-6)=0

We add all the numbers together, and all the variables

-4x-2(x+4)-(7+3(x+5)-6)+6=0

We multiply parentheses

-4x-2x-(7+3(x+5)-6)-8+6=0



We calculate terms in parentheses: -(7+3(x+5)-6), so:

7+3(x+5)-6

determiningTheFunctionDomain
3(x+5)+7-6

We add all the numbers together, and all the variables

3(x+5)+1

We multiply parentheses

3x+15+1

We add all the numbers together, and all the variables

3x+16

Back to the equation:

-(3x+16)



We add all the numbers together, and all the variables

-6x-(3x+16)-2=0

We get rid of parentheses

-6x-3x-16-2=0

We add all the numbers together, and all the variables

-9x-18=0

We move all terms containing x to the left, all other terms to the right

-9x=18

x=18/-9

x=-2

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