6-2(x-0.5)=3(x-1/6)-5

Solution for 6-2(x-0.5)=3(x-1/6)-5 equation:

6-2(x-0.5)=3(x-1/6)-5

We move all terms to the left:

6-2(x-0.5)-(3(x-1/6)-5)=0

We add all the numbers together, and all the variables

-2(x-0.5)-(3(+x-1/6)-5)+6=0

We multiply parentheses

-2x-(3(+x-1/6)-5)+1+6=0

We multiply all the terms by the denominator


-2x*6)-5)-(3(+x-1+1*6)-5)+6*6)-5)=0

We add all the numbers together, and all the variables

-2x*6)-5)-(3(x+5)-5)+6*6)-5)=0

We add all the numbers together, and all the variables

-2x*6)-5)-(3(x=0

Wy multiply elements

-12x^2=0

a = -12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-12)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-24}=0$