6-2(x-2)=5(x+3)+10

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Solution for 6-2(x-2)=5(x+3)+10 equation: 



6-2(x-2)=5(x+3)+10

We move all terms to the left:

6-2(x-2)-(5(x+3)+10)=0

We multiply parentheses

-2x-(5(x+3)+10)+4+6=0



We calculate terms in parentheses: -(5(x+3)+10), so:

5(x+3)+10

We multiply parentheses

5x+15+10

We add all the numbers together, and all the variables

5x+25

Back to the equation:

-(5x+25)



We add all the numbers together, and all the variables

-2x-(5x+25)+10=0

We get rid of parentheses

-2x-5x-25+10=0

We add all the numbers together, and all the variables

-7x-15=0

We move all terms containing x to the left, all other terms to the right

-7x=15

x=15/-7

x=-2+1/7

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