6-2(x-3)=-4x-4+12

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Solution for 6-2(x-3)=-4x-4+12 equation:



6-2(x-3)=-4x-4+12
We move all terms to the left:
6-2(x-3)-(-4x-4+12)=0
We add all the numbers together, and all the variables
-2(x-3)-(-4x+8)+6=0
We multiply parentheses
-2x-(-4x+8)+6+6=0
We get rid of parentheses
-2x+4x-8+6+6=0
We add all the numbers together, and all the variables
2x+4=0
We move all terms containing x to the left, all other terms to the right
2x=-4
x=-4/2
x=-2

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