6-2(x-3)=-4x-4+12

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Solution for 6-2(x-3)=-4x-4+12 equation: 



6-2(x-3)=-4x-4+12

We move all terms to the left:

6-2(x-3)-(-4x-4+12)=0

We add all the numbers together, and all the variables

-2(x-3)-(-4x+8)+6=0

We multiply parentheses

-2x-(-4x+8)+6+6=0

We get rid of parentheses

-2x+4x-8+6+6=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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