6-2(x-3)=4(x-5)

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Solution for 6-2(x-3)=4(x-5) equation: 



6-2(x-3)=4(x-5)

We move all terms to the left:

6-2(x-3)-(4(x-5))=0

We multiply parentheses

-2x-(4(x-5))+6+6=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We add all the numbers together, and all the variables

-2x-(4x-20)+12=0

We get rid of parentheses

-2x-4x+20+12=0

We add all the numbers together, and all the variables

-6x+32=0

We move all terms containing x to the left, all other terms to the right

-6x=-32

x=-32/-6

x=5+1/3

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