6-2n=1+4(n-5)

Solution for 6-2n=1+4(n-5) equation:

6-2n=1+4(n-5)

We move all terms to the left:

6-2n-(1+4(n-5))=0


We calculate terms in parentheses: -(1+4(n-5)), so:

1+4(n-5)

determiningTheFunctionDomain
4(n-5)+1

We multiply parentheses

4n-20+1

We add all the numbers together, and all the variables

4n-19

Back to the equation:

-(4n-19)


We get rid of parentheses

-2n-4n+19+6=0

We add all the numbers together, and all the variables

-6n+25=0

We move all terms containing n to the left, all other terms to the right

-6n=-25

n=-25/-6

n=4+1/6