6-2x-3(x-4)+2=0

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Solution for 6-2x-3(x-4)+2=0 equation: 



6-2x-3(x-4)+2=0

We add all the numbers together, and all the variables

-2x-3(x-4)+8=0

We multiply parentheses

-2x-3x+12+8=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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