6-2y=(3y-4)10

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Solution for 6-2y=(3y-4)10 equation: 



6-2y=(3y-4)10

We move all terms to the left:

6-2y-((3y-4)10)=0



We calculate terms in parentheses: -((3y-4)10), so:

(3y-4)10

We multiply parentheses

30y-40

Back to the equation:

-(30y-40)



We get rid of parentheses

-2y-30y+40+6=0

We add all the numbers together, and all the variables

-32y+46=0

We move all terms containing y to the left, all other terms to the right

-32y=-46

y=-46/-32

y=1+7/16

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