6-3(2w+1)=10w-4(10+w)

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Solution for 6-3(2w+1)=10w-4(10+w) equation: 



6-3(2w+1)=10w-4(10+w)

We move all terms to the left:

6-3(2w+1)-(10w-4(10+w))=0

We add all the numbers together, and all the variables

-3(2w+1)-(10w-4(w+10))+6=0

We multiply parentheses

-6w-(10w-4(w+10))-3+6=0



We calculate terms in parentheses: -(10w-4(w+10)), so:

10w-4(w+10)

We multiply parentheses

10w-4w-40

We add all the numbers together, and all the variables

6w-40

Back to the equation:

-(6w-40)



We add all the numbers together, and all the variables

-6w-(6w-40)+3=0

We get rid of parentheses

-6w-6w+40+3=0

We add all the numbers together, and all the variables

-12w+43=0

We move all terms containing w to the left, all other terms to the right

-12w=-43

w=-43/-12

w=3+7/12

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