6-3(2x+2)=4(8-x)

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Solution for 6-3(2x+2)=4(8-x) equation: 



6-3(2x+2)=4(8-x)

We move all terms to the left:

6-3(2x+2)-(4(8-x))=0

We add all the numbers together, and all the variables

-3(2x+2)-(4(-1x+8))+6=0

We multiply parentheses

-6x-(4(-1x+8))-6+6=0



We calculate terms in parentheses: -(4(-1x+8)), so:

4(-1x+8)

We multiply parentheses

-4x+32

Back to the equation:

-(-4x+32)



We add all the numbers together, and all the variables

-6x-(-4x+32)=0

We get rid of parentheses

-6x+4x-32=0

We add all the numbers together, and all the variables

-2x-32=0

We move all terms containing x to the left, all other terms to the right

-2x=32

x=32/-2

x=-16

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