6-3(4k+1)=(10-8k)+5

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Solution for 6-3(4k+1)=(10-8k)+5 equation: 



6-3(4k+1)=(10-8k)+5

We move all terms to the left:

6-3(4k+1)-((10-8k)+5)=0

We add all the numbers together, and all the variables

-3(4k+1)-((-8k+10)+5)+6=0

We multiply parentheses

-12k-((-8k+10)+5)-3+6=0



We calculate terms in parentheses: -((-8k+10)+5), so:

(-8k+10)+5

We get rid of parentheses

-8k+10+5

We add all the numbers together, and all the variables

-8k+15

Back to the equation:

-(-8k+15)



We add all the numbers together, and all the variables

-12k-(-8k+15)+3=0

We get rid of parentheses

-12k+8k-15+3=0

We add all the numbers together, and all the variables

-4k-12=0

We move all terms containing k to the left, all other terms to the right

-4k=12

k=12/-4

k=-3

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