6-3(j-1)+5(j+3)=10

Solution for 6-3(j-1)+5(j+3)=10 equation:

Simplifying
6 + -3(j + -1) + 5(j + 3) = 10

Reorder the terms:
6 + -3(-1 + j) + 5(j + 3) = 10
6 + (-1 * -3 + j * -3) + 5(j + 3) = 10
6 + (3 + -3j) + 5(j + 3) = 10

Reorder the terms:
6 + 3 + -3j + 5(3 + j) = 10
6 + 3 + -3j + (3 * 5 + j * 5) = 10
6 + 3 + -3j + (15 + 5j) = 10

Reorder the terms:
6 + 3 + 15 + -3j + 5j = 10

Combine like terms: 6 + 3 = 9
9 + 15 + -3j + 5j = 10

Combine like terms: 9 + 15 = 24
24 + -3j + 5j = 10

Combine like terms: -3j + 5j = 2j
24 + 2j = 10

Solving
24 + 2j = 10

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-24' to each side of the equation.
24 + -24 + 2j = 10 + -24

Combine like terms: 24 + -24 = 0
0 + 2j = 10 + -24
2j = 10 + -24

Combine like terms: 10 + -24 = -14
2j = -14

Divide each side by '2'.
j = -7

Simplifying
j = -7