6-3(r+2)=5(r+3)+1

Solution for 6-3(r+2)=5(r+3)+1 equation:

Simplifying
6 + -3(r + 2) = 5(r + 3) + 1

Reorder the terms:
6 + -3(2 + r) = 5(r + 3) + 1
6 + (2 * -3 + r * -3) = 5(r + 3) + 1
6 + (-6 + -3r) = 5(r + 3) + 1

Combine like terms: 6 + -6 = 0
0 + -3r = 5(r + 3) + 1
-3r = 5(r + 3) + 1

Reorder the terms:
-3r = 5(3 + r) + 1
-3r = (3 * 5 + r * 5) + 1
-3r = (15 + 5r) + 1

Reorder the terms:
-3r = 15 + 1 + 5r

Combine like terms: 15 + 1 = 16
-3r = 16 + 5r

Solving
-3r = 16 + 5r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-5r' to each side of the equation.
-3r + -5r = 16 + 5r + -5r

Combine like terms: -3r + -5r = -8r
-8r = 16 + 5r + -5r

Combine like terms: 5r + -5r = 0
-8r = 16 + 0
-8r = 16

Divide each side by '-8'.
r = -2

Simplifying
r = -2