6-3(x+1)=4x+2(1-x)

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Solution for 6-3(x+1)=4x+2(1-x) equation: 



6-3(x+1)=4x+2(1-x)

We move all terms to the left:

6-3(x+1)-(4x+2(1-x))=0

We add all the numbers together, and all the variables

-3(x+1)-(4x+2(-1x+1))+6=0

We multiply parentheses

-3x-(4x+2(-1x+1))-3+6=0



We calculate terms in parentheses: -(4x+2(-1x+1)), so:

4x+2(-1x+1)

We multiply parentheses

4x-2x+2

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

-3x-(2x+2)+3=0

We get rid of parentheses

-3x-2x-2+3=0

We add all the numbers together, and all the variables

-5x+1=0

We move all terms containing x to the left, all other terms to the right

-5x=-1

x=-1/-5

x=1/5

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