6-3(x+2)+4(x-5)=10

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Solution for 6-3(x+2)+4(x-5)=10 equation: 


Simplifying
6 + -3(x + 2) + 4(x + -5) = 10

Reorder the terms:
6 + -3(2 + x) + 4(x + -5) = 10
6 + (2 * -3 + x * -3) + 4(x + -5) = 10
6 + (-6 + -3x) + 4(x + -5) = 10

Reorder the terms:
6 + -6 + -3x + 4(-5 + x) = 10
6 + -6 + -3x + (-5 * 4 + x * 4) = 10
6 + -6 + -3x + (-20 + 4x) = 10

Reorder the terms:
6 + -6 + -20 + -3x + 4x = 10

Combine like terms: 6 + -6 = 0
0 + -20 + -3x + 4x = 10
-20 + -3x + 4x = 10

Combine like terms: -3x + 4x = 1x
-20 + 1x = 10

Solving
-20 + 1x = 10

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 1x = 10 + 20

Combine like terms: -20 + 20 = 0
0 + 1x = 10 + 20
1x = 10 + 20

Combine like terms: 10 + 20 = 30
1x = 30

Divide each side by '1'.
x = 30

Simplifying
x = 30

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