6-3(x+2)=2(3x-4)-10

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Solution for 6-3(x+2)=2(3x-4)-10 equation: 



6-3(x+2)=2(3x-4)-10

We move all terms to the left:

6-3(x+2)-(2(3x-4)-10)=0

We multiply parentheses

-3x-(2(3x-4)-10)-6+6=0



We calculate terms in parentheses: -(2(3x-4)-10), so:

2(3x-4)-10

We multiply parentheses

6x-8-10

We add all the numbers together, and all the variables

6x-18

Back to the equation:

-(6x-18)



We add all the numbers together, and all the variables

-3x-(6x-18)=0

We get rid of parentheses

-3x-6x+18=0

We add all the numbers together, and all the variables

-9x+18=0

We move all terms containing x to the left, all other terms to the right

-9x=-18

x=-18/-9

x=+2

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