6-3(x-8)+7x=2(x+4)+2

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Solution for 6-3(x-8)+7x=2(x+4)+2 equation: 



6-3(x-8)+7x=2(x+4)+2

We move all terms to the left:

6-3(x-8)+7x-(2(x+4)+2)=0

We add all the numbers together, and all the variables

7x-3(x-8)-(2(x+4)+2)+6=0

We multiply parentheses

7x-3x-(2(x+4)+2)+24+6=0



We calculate terms in parentheses: -(2(x+4)+2), so:

2(x+4)+2

We multiply parentheses

2x+8+2

We add all the numbers together, and all the variables

2x+10

Back to the equation:

-(2x+10)



We add all the numbers together, and all the variables

4x-(2x+10)+30=0

We get rid of parentheses

4x-2x-10+30=0

We add all the numbers together, and all the variables

2x+20=0

We move all terms containing x to the left, all other terms to the right

2x=-20

x=-20/2

x=-10

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