6-4(2m+7)+8=7m-4(m+2)

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Solution for 6-4(2m+7)+8=7m-4(m+2) equation: 



6-4(2m+7)+8=7m-4(m+2)

We move all terms to the left:

6-4(2m+7)+8-(7m-4(m+2))=0

We add all the numbers together, and all the variables

-4(2m+7)-(7m-4(m+2))+14=0

We multiply parentheses

-8m-(7m-4(m+2))-28+14=0



We calculate terms in parentheses: -(7m-4(m+2)), so:

7m-4(m+2)

We multiply parentheses

7m-4m-8

We add all the numbers together, and all the variables

3m-8

Back to the equation:

-(3m-8)



We add all the numbers together, and all the variables

-8m-(3m-8)-14=0

We get rid of parentheses

-8m-3m+8-14=0

We add all the numbers together, and all the variables

-11m-6=0

We move all terms containing m to the left, all other terms to the right

-11m=6

m=6/-11

m=-6/11

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