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6-4(2x-3)=3(x+1)
We move all terms to the left:
6-4(2x-3)-(3(x+1))=0
We multiply parentheses
-8x-(3(x+1))+12+6=0
We calculate terms in parentheses: -(3(x+1)), so:We add all the numbers together, and all the variables
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
-8x-(3x+3)+18=0
We get rid of parentheses
-8x-3x-3+18=0
We add all the numbers together, and all the variables
-11x+15=0
We move all terms containing x to the left, all other terms to the right
-11x=-15
x=-15/-11
x=1+4/11
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