6-4(2x-3)=3(x+1)

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Solution for 6-4(2x-3)=3(x+1) equation: 



6-4(2x-3)=3(x+1)

We move all terms to the left:

6-4(2x-3)-(3(x+1))=0

We multiply parentheses

-8x-(3(x+1))+12+6=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

-8x-(3x+3)+18=0

We get rid of parentheses

-8x-3x-3+18=0

We add all the numbers together, and all the variables

-11x+15=0

We move all terms containing x to the left, all other terms to the right

-11x=-15

x=-15/-11

x=1+4/11

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