6-4(c-2)=2(c+1)-c

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Solution for 6-4(c-2)=2(c+1)-c equation:



6-4(c-2)=2(c+1)-c
We move all terms to the left:
6-4(c-2)-(2(c+1)-c)=0
We multiply parentheses
-4c-(2(c+1)-c)+8+6=0
We calculate terms in parentheses: -(2(c+1)-c), so:
2(c+1)-c
We add all the numbers together, and all the variables
-1c+2(c+1)
We multiply parentheses
-1c+2c+2
We add all the numbers together, and all the variables
c+2
Back to the equation:
-(c+2)
We add all the numbers together, and all the variables
-4c-(c+2)+14=0
We get rid of parentheses
-4c-c-2+14=0
We add all the numbers together, and all the variables
-5c+12=0
We move all terms containing c to the left, all other terms to the right
-5c=-12
c=-12/-5
c=2+2/5

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