6-4(n-3)=2(1-2n)+16

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Solution for 6-4(n-3)=2(1-2n)+16 equation: 


Simplifying
6 + -4(n + -3) = 2(1 + -2n) + 16

Reorder the terms:
6 + -4(-3 + n) = 2(1 + -2n) + 16
6 + (-3 * -4 + n * -4) = 2(1 + -2n) + 16
6 + (12 + -4n) = 2(1 + -2n) + 16

Combine like terms: 6 + 12 = 18
18 + -4n = 2(1 + -2n) + 16
18 + -4n = (1 * 2 + -2n * 2) + 16
18 + -4n = (2 + -4n) + 16

Reorder the terms:
18 + -4n = 2 + 16 + -4n

Combine like terms: 2 + 16 = 18
18 + -4n = 18 + -4n

Add '-18' to each side of the equation.
18 + -18 + -4n = 18 + -18 + -4n

Combine like terms: 18 + -18 = 0
0 + -4n = 18 + -18 + -4n
-4n = 18 + -18 + -4n

Combine like terms: 18 + -18 = 0
-4n = 0 + -4n
-4n = -4n

Add '4n' to each side of the equation.
-4n + 4n = -4n + 4n

Combine like terms: -4n + 4n = 0
0 = -4n + 4n

Combine like terms: -4n + 4n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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