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6-4(x+2)=9+3(5x-10)
We move all terms to the left:
6-4(x+2)-(9+3(5x-10))=0
We multiply parentheses
-4x-(9+3(5x-10))-8+6=0
We calculate terms in parentheses: -(9+3(5x-10)), so:We add all the numbers together, and all the variables
9+3(5x-10)
determiningTheFunctionDomain 3(5x-10)+9
We multiply parentheses
15x-30+9
We add all the numbers together, and all the variables
15x-21
Back to the equation:
-(15x-21)
-4x-(15x-21)-2=0
We get rid of parentheses
-4x-15x+21-2=0
We add all the numbers together, and all the variables
-19x+19=0
We move all terms containing x to the left, all other terms to the right
-19x=-19
x=-19/-19
x=1
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