6-4(x-2)+8x=2(x+6)

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Solution for 6-4(x-2)+8x=2(x+6) equation: 



6-4(x-2)+8x=2(x+6)

We move all terms to the left:

6-4(x-2)+8x-(2(x+6))=0

We add all the numbers together, and all the variables

8x-4(x-2)-(2(x+6))+6=0

We multiply parentheses

8x-4x-(2(x+6))+8+6=0



We calculate terms in parentheses: -(2(x+6)), so:

2(x+6)

We multiply parentheses

2x+12

Back to the equation:

-(2x+12)



We add all the numbers together, and all the variables

4x-(2x+12)+14=0

We get rid of parentheses

4x-2x-12+14=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

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