6-4(y+13)=2(y-1)

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Solution for 6-4(y+13)=2(y-1) equation: 



6-4(y+13)=2(y-1)

We move all terms to the left:

6-4(y+13)-(2(y-1))=0

We multiply parentheses

-4y-(2(y-1))-52+6=0



We calculate terms in parentheses: -(2(y-1)), so:

2(y-1)

We multiply parentheses

2y-2

Back to the equation:

-(2y-2)



We add all the numbers together, and all the variables

-4y-(2y-2)-46=0

We get rid of parentheses

-4y-2y+2-46=0

We add all the numbers together, and all the variables

-6y-44=0

We move all terms containing y to the left, all other terms to the right

-6y=44

y=44/-6

y=-7+1/3

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