6-4/(a+2)=8+a

Solution for 6-4/(a+2)=8+a equation:

6-4/(a+2)=8+a

We move all terms to the left:

6-4/(a+2)-(8+a)=0


Domain of the equation: (a+2)!=0

We move all terms containing a to the left, all other terms to the right

a!=-2

a∈R


We add all the numbers together, and all the variables

-4/(a+2)-(a+8)+6=0

We get rid of parentheses

-4/(a+2)-a-8+6=0

We multiply all the terms by the denominator


-a*(a+2)-8*(a+2)+6*(a+2)-4=0

We multiply parentheses

-a^2-2a-8a+6a-16+12-4=0

We add all the numbers together, and all the variables

-1a^2-4a-8=0

a = -1; b = -4; c = -8;
Δ = b2-4ac
Δ = -42-4·(-1)·(-8)
Δ = -16
Delta is less than zero, so there is no solution for the equation