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6-4/5x=8-1/10x
We move all terms to the left:
6-4/5x-(8-1/10x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-4/5x-(-1/10x+8)+6=0
We get rid of parentheses
-4/5x+1/10x-8+6=0
We calculate fractions
(-40x)/50x^2+5x/50x^2-8+6=0
We add all the numbers together, and all the variables
(-40x)/50x^2+5x/50x^2-2=0
We multiply all the terms by the denominator
(-40x)+5x-2*50x^2=0
We add all the numbers together, and all the variables
5x+(-40x)-2*50x^2=0
Wy multiply elements
-100x^2+5x+(-40x)=0
We get rid of parentheses
-100x^2+5x-40x=0
We add all the numbers together, and all the variables
-100x^2-35x=0
a = -100; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·(-100)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*-100}=\frac{0}{-200} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*-100}=\frac{70}{-200} =-7/20 $
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