6-5(4d-3)=7(3-4d)+8

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Solution for 6-5(4d-3)=7(3-4d)+8 equation: 



6-5(4d-3)=7(3-4d)+8

We move all terms to the left:

6-5(4d-3)-(7(3-4d)+8)=0

We add all the numbers together, and all the variables

-5(4d-3)-(7(-4d+3)+8)+6=0

We multiply parentheses

-20d-(7(-4d+3)+8)+15+6=0



We calculate terms in parentheses: -(7(-4d+3)+8), so:

7(-4d+3)+8

We multiply parentheses

-28d+21+8

We add all the numbers together, and all the variables

-28d+29

Back to the equation:

-(-28d+29)



We add all the numbers together, and all the variables

-20d-(-28d+29)+21=0

We get rid of parentheses

-20d+28d-29+21=0

We add all the numbers together, and all the variables

8d-8=0

We move all terms containing d to the left, all other terms to the right

8d=8

d=8/8

d=1

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