6-5(x-2)=-6(x-1)+(x+10)

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Solution for 6-5(x-2)=-6(x-1)+(x+10) equation: 



6-5(x-2)=-6(x-1)+(x+10)

We move all terms to the left:

6-5(x-2)-(-6(x-1)+(x+10))=0

We multiply parentheses

-5x-(-6(x-1)+(x+10))+10+6=0



We calculate terms in parentheses: -(-6(x-1)+(x+10)), so:

-6(x-1)+(x+10)

We multiply parentheses

-6x+(x+10)+6

We get rid of parentheses

-6x+x+10+6

We add all the numbers together, and all the variables

-5x+16

Back to the equation:

-(-5x+16)



We add all the numbers together, and all the variables

-5x-(-5x+16)+16=0

We get rid of parentheses

-5x+5x-16+16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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