6-5(x-2)=2/3(3x+12)

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Solution for 6-5(x-2)=2/3(3x+12) equation: 



6-5(x-2)=2/3(3x+12)

We move all terms to the left:

6-5(x-2)-(2/3(3x+12))=0



Domain of the equation: 3(3x+12))!=0

x∈R



We multiply parentheses

-5x-(2/3(3x+12))+10+6=0

We multiply all the terms by the denominator


-5x*3(3x+12))-(2+10*3(3x+12))+6*3(3x+12))=0

We add all the numbers together, and all the variables

-5x*3(3x+12))-(2+10*3(3x+12))+6*3(3x=0

Wy multiply elements

-15x^2(3+90x^2(3=0

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